a-4[b-2(c-x)]=6

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Solution for a-4[b-2(c-x)]=6 equation:


Simplifying
a + -4[b + -2(c + -1x)] = 6
a + -4[b + (c * -2 + -1x * -2)] = 6
a + -4[b + (-2c + 2x)] = 6
a + [b * -4 + -2c * -4 + 2x * -4] = 6
a + [-4b + 8c + -8x] = 6

Solving
a + -4b + 8c + -8x = 6

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '4b' to each side of the equation.
a + -4b + 8c + 4b + -8x = 6 + 4b

Reorder the terms:
a + -4b + 4b + 8c + -8x = 6 + 4b

Combine like terms: -4b + 4b = 0
a + 0 + 8c + -8x = 6 + 4b
a + 8c + -8x = 6 + 4b

Add '-8c' to each side of the equation.
a + 8c + -8c + -8x = 6 + 4b + -8c

Combine like terms: 8c + -8c = 0
a + 0 + -8x = 6 + 4b + -8c
a + -8x = 6 + 4b + -8c

Add '8x' to each side of the equation.
a + -8x + 8x = 6 + 4b + -8c + 8x

Combine like terms: -8x + 8x = 0
a + 0 = 6 + 4b + -8c + 8x
a = 6 + 4b + -8c + 8x

Simplifying
a = 6 + 4b + -8c + 8x

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